(u^2-12u+35)/(3u^2-30u+63)

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Solution for (u^2-12u+35)/(3u^2-30u+63) equation:


D( u )

3*u^2-(30*u)+63 = 0

3*u^2-(30*u)+63 = 0

3*u^2-(30*u)+63 = 0

3*u^2-30*u+63 = 0

3*u^2-30*u+63 = 0

DELTA = (-30)^2-(3*4*63)

DELTA = 144

DELTA > 0

u = (144^(1/2)+30)/(2*3) or u = (30-144^(1/2))/(2*3)

u = 7 or u = 3

u in (-oo:3) U (3:7) U (7:+oo)

(u^2-(12*u)+35)/(3*u^2-(30*u)+63) = 0

(u^2-12*u+35)/(3*u^2-30*u+63) = 0

u^2-12*u+35 = 0

u^2-12*u+35 = 0

DELTA = (-12)^2-(1*4*35)

DELTA = 4

DELTA > 0

u = (4^(1/2)+12)/(1*2) or u = (12-4^(1/2))/(1*2)

u = 7 or u = 5

(u-5)*(u-7) = 0

3*u^2-30*u+63 = 0

3*(u^2-10*u+21) = 0

u^2-10*u+21 = 0

DELTA = (-10)^2-(1*4*21)

DELTA = 16

DELTA > 0

u = (16^(1/2)+10)/(1*2) or u = (10-16^(1/2))/(1*2)

u = 7 or u = 3

3*(u-3)*(u-7) = 0

((u-5)*(u-7))/(3*(u-3)*(u-7)) = 0

( u-5 )

u-5 = 0 // + 5

u = 5

( u-7 )

u-7 = 0 // + 7

u = 7

u in { 7}

u = 5

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